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Sagot :
The magnitude of the force experienced by a 1. 0 c charge placed at the location of the test charge is 4.5*10^8N.
To find the answer, we have to know more about the force experienced between two charges.
How to find the force experienced between two charges?
- It is given that,
[tex]Q_1=5C\\Q_2=1C\\r=10m.[/tex]
- We have to find the force experienced between two charges,
[tex]F=\frac{kQ_1Q_2}{r^2}[/tex]
where, k=8.99*10^9.
- Thus, by substitution, the force will be,
[tex]F=\frac{8.99*10^9*5*1}{10^2} =4.5*10^8N[/tex]
Thus, we can conclude that, the magnitude of the force experienced by a 1. 0 c charge placed at the location of the test charge is 4.5*10^8N.
Learn more about the force here:
https://brainly.com/question/4086258
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