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Sagot :
The potential difference comes out to be
[tex]10 \times 10 {}^{ - 3} m[/tex]
Given:
σ = 8. 85 × 10-9 c/m2
we know,
[tex]E = \frac{σ}{2ε0}[/tex]
[tex]E = \frac{8.85 \times 10 {}^{ - 9} }{2ε0}[/tex]
[tex]E = \frac{v}{d} [/tex]
given the potential difference between two equipotential surface=5v
E=∆v
∆d=∆v/E
[tex] = \frac{5 \times 8.85 \times 10 { }^{ - 12} \times 2 }{8.85 \times 10 {}^{ - 9} } [/tex]
[tex]Δ = 10 \times 10 {}^{ - 3} m[/tex]
Thus the potential difference is
[tex]10 \times 10 {}^{ - 3} m[/tex]
Learn more about potential difference from here: https://brainly.com/question/28165869
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