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Sagot :
The speed of the moving walkway relative to the airport terminal exists at 1.84 m/s.
How to estimate the speed of the moving walkway relative to the airport terminal?
Let x be the speed of the walkway.
(2.8 + x) = speed of child moving in direction of the walkway
(2.8 - x) = speed of child moving against the direction of the walkway
Travel time = distance/speed
Travel time of child moving in direction of walkway = 23/(2.8+x)
Total elapsed time given = 29s
23/(2.8 + x)+ 23 / (2.8-x) = 29
LCD = (2.8 + x)(2.8 - x)
[tex]23(2.8 - x) + 23(2.8 + x) = 29(2.8 + x)(2.8 -x)[/tex]
simplifying the equation, we get
[tex]23*2.8-23x+23*2.8+23x=29(2.8^2-x^2)[/tex]
[tex]23(2.8+2.8)/29=2.8^2-x^2[/tex]
[tex]x^2=(2.8)^2-(23*5.6)/29)=3.4[/tex]
[tex]x=\sqrt{3.4}=1.84m/s[/tex]
Speed of walkway = 1.84 m/s
The speed of the moving walkway relative to the airport terminal exists at 1.84 m/s.
To learn more about Speed refer to:
brainly.com/question/4931057
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