Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Get the answers you need quickly and accurately from a dedicated community of experts on our Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
The Henderson-hasselbalch equation for a propanoic acid solution is expressed as [A-]/[HA] = 2.7.
What is Henderson Hasselbalch Equation ?
It is expressed as:
pH = pKa + log([A-]/[HA].
where,
[A-] is molar concentration of conjugate base and
[HA] is molar concentration of weak acid.
Given,
pH = 5.30
Substitute the value in the Henderson Hasselbalch equation
5.30 = 4.874 + log[A-]/ [HA]
log[A-]/[HA] = 5.30 - 4.874
[A-]/[HA] = 10^ 0.426
[A-]/[HA] = 2.7
Thus from the conclusion we can say that The henderson-hasselbalch equation for a propanoic acid solution is expressed as [A-]/[HA] = 2.7.
Learn more about Henderson Hasselbalch equation here:
https://brainly.com/question/13423434
#SPJ4
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.
