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Sagot :
The density of the oil is 917kg/ m³.
An object is said to be naturally buoyant when ithas the tendency to float in a fluid.
from the law of floating when a body float in a liquid,the weight of the liquid displaced by its immersed part is equal to the total weight of body.
That is
weight (w)=upthrust (u)
w=u
therefore
u=Dvg
where, D= density of the ice
v= volume of ice
g= acceleration due to gravity
from the question
given:
D = 917kg/m {}^{3} [/tex]
v = 3.00cm {}^{3} [/tex]
g = 9.8m/s {}^{2} [/tex]
substitute these values in above equation
u = 917(3 \times 10 {}^{ - 6} )(9.8)[/tex]
u=0.027N
but,
upthrust= weight of oil displaced.And the ice will displaced an amount of oil,equal to its own weight.
therefore,
density of oil = u/gv = (0.027)/3 \times 10 {}^{ - 6)} (9.8)[/tex]
density of oil = 917kg/m {}^{3} [/tex]
hence the density of the oil is 917kg/m {}^{3} [/tex]
learn more about density from here: https://brainly.com/question/28166066
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