Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Explore a wealth of knowledge from professionals across different disciplines on our comprehensive platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
The density of the oil is 917kg/ m³.
An object is said to be naturally buoyant when ithas the tendency to float in a fluid.
from the law of floating when a body float in a liquid,the weight of the liquid displaced by its immersed part is equal to the total weight of body.
That is
weight (w)=upthrust (u)
w=u
therefore
u=Dvg
where, D= density of the ice
v= volume of ice
g= acceleration due to gravity
from the question
given:
D = 917kg/m {}^{3} [/tex]
v = 3.00cm {}^{3} [/tex]
g = 9.8m/s {}^{2} [/tex]
substitute these values in above equation
u = 917(3 \times 10 {}^{ - 6} )(9.8)[/tex]
u=0.027N
but,
upthrust= weight of oil displaced.And the ice will displaced an amount of oil,equal to its own weight.
therefore,
density of oil = u/gv = (0.027)/3 \times 10 {}^{ - 6)} (9.8)[/tex]
density of oil = 917kg/m {}^{3} [/tex]
hence the density of the oil is 917kg/m {}^{3} [/tex]
learn more about density from here: https://brainly.com/question/28166066
#SPJ4
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We hope this was helpful. Please come back whenever you need more information or answers to your queries. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.