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In state n = 1, the energy of the hydrogen atom is -13. 58 ev. what is its energy in state n = 2?

Sagot :

In state n = 1, the energy of the hydrogen atom is -13. 58 ev, then the energy in state n = 2 is -3.40eV.

For an electron located in an inner orbit to jump an upper orbit, it needs an energy equal to the difference between the two quantized orbits. This energy comes from the absorption of a photon with the same energy required. The formula for the energy levels of a Hydrogen atom is:

En = E/(n×n)

where E is the energy of the ground state and n is the energy level or state. Then the energy in n= 1 is

En = -13. 58/ 4

En = -3. 40eV

Thus, we find the value of energy of hydrogen atom in n=2 is -3. 40eV.

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