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A spring with a constant k=400n/m shoots a 1. 00kg ball up a frictionless incline after being compressed 0. 150m. what is the maximum height reached by the ball?

Sagot :

tanisharawat014

The maximum height reached by the ball is 0.46m.

To find the answer, we have to know about the potential energy of a spring mass system.

How to find the maximum height reached by the ball?

  • It is given that,

                       [tex]k=400N/m\\m=1kg\\x=0.150m\\h=?\\[/tex]

  • We have to find the maximum height reached by the ball.
  • Thus, we have the expression for potential energy of a spring mass system and that of gravitational field as,

                             [tex]U=\frac{1}{2}kx^2 \\U=mgh[/tex]

  • Combining both, we get,

                    [tex]h=\frac{kx^2}{2mg} =\frac{400*(0.15)^2}{2*1*9.8} =0.46m[/tex]

Thus, we can conclude that, the maximum height reached by the ball is 0.46m.

Learn more about the potential energy here:

https://brainly.com/question/26962934

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