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Glycerin at a temperature of 30 degrees celcius flows at a rate of 8×10−6m3/s through a horizontal tube with a 30mm diameter. what is the pressure drop in pascals per 100m?

Sagot :

tanisharawat014

The pressure drop in pascal is 3.824*10^4 Pascals.

To find the answer, we need to know about the Poiseuille's formula.

How to find the pressure drop in pascal?

  • We have the Poiseuille's formula,

                      [tex]Q=\frac{\pi Pr^4}{8\beta l}[/tex]

where, Q is the rate of flow, P is the pressure drop, r is the radius of the pipe, [tex]\beta[/tex] is the coefficient of viscosity (0.95Pas-s for Glycerin) and l being the length of the tube.

  • It is given that,

                [tex]Q=8*10^{-6}m^3/s\\diameter=30mm, thus,\\r=15mm\\l=100m\\\beta =0.95[/tex]

  • Thus, the pressure drop will be,

                [tex]P=\frac{8Q\beta l}{\pi r^4} =\frac{8*8*10^{-6}*0.95*100}{3.14*(15*10^{-3})^4} \\\\P=3.824*10^4Pascals.[/tex]

Thus, we can conclude that, the pressure drop in pascal is 3.824*10^4 Pascals.

Learn more about the Poiseuille's formula here:

https://brainly.com/question/13180459

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