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Sagot :
The de Broglie wavelength of the particle is 1.578*10^-3nm.
To find the answer, we have to know about the de Broglie wavelength.
How to find the de Broglie wavelength?
- We have the expression for de Broglie wavelength as,
[tex]wavelength=\frac{h}{P} =\frac{h}{mv}[/tex]
where, h is the plank's constant, m is the mass and v is the velocity.
- It is given that,
[tex]m=3.5*10^{-28}kg\\a=2.4*10^7m/s^2\\t=5s\\h=6.63*10^{-34}Js[/tex]
- Substituting the values, we get,
[tex]wavelength=\frac{6.63*10^{-34}}{3.5*10^{-28}*2.4*10^7*5}=1.578*10^{-14}m\\\\ wavelength=1.578*10^{-3}nm.[/tex]
Thus, we can conclude that, the de Broglie wavelength of the particle is 1.578*10^-3nm.
Learn more about the the de Broglie wavelength here:
https://brainly.com/question/16595523
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