Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
The de Broglie wavelength of the particle is 1.578*10^-3nm.
To find the answer, we have to know about the de Broglie wavelength.
How to find the de Broglie wavelength?
- We have the expression for de Broglie wavelength as,
[tex]wavelength=\frac{h}{P} =\frac{h}{mv}[/tex]
where, h is the plank's constant, m is the mass and v is the velocity.
- It is given that,
[tex]m=3.5*10^{-28}kg\\a=2.4*10^7m/s^2\\t=5s\\h=6.63*10^{-34}Js[/tex]
- Substituting the values, we get,
[tex]wavelength=\frac{6.63*10^{-34}}{3.5*10^{-28}*2.4*10^7*5}=1.578*10^{-14}m\\\\ wavelength=1.578*10^{-3}nm.[/tex]
Thus, we can conclude that, the de Broglie wavelength of the particle is 1.578*10^-3nm.
Learn more about the the de Broglie wavelength here:
https://brainly.com/question/16595523
#SPJ4
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.