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A circular loop of wire of radius 10 cm carries a current of 6. 0 a. what is the magnitude of the magnetic field at the center of the loop? (μ0 = 4π × 10-7 t ∙ m/a)

Sagot :

The magnitude of the magnetic field at the center of the loop is [tex]3.77*10^{-5} T[/tex]

Given,

μ0 = 4π × [tex]10^{-7}[/tex] t ∙ m/a, I=6 A, R = 10cm =0.1m

magnetic field(B)=μ0*I/2R=[tex]\frac{4*3.14*10x^{-7}*6 }{2*0.1}[/tex]=[tex]3.77*10^{-5} T[/tex]

Magnetic field

When it comes to the magnetic influence on moving electric charges, electric currents, and magnetic materials, we use the vector field of a magnetic field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is travelling in a magnetic field. Iron and other ferromagnetic elements are drawn to a permanent magnet's magnetic field, which also draws or repels other magnets. Furthermore, a magnetic field with varying localization will impose a force on a variety of non-magnetic materials by altering the velocity of their outer atomic electrons. Magnetic fields surround magnetised materials and are produced by electric currents, like those found in electromagnets, and by electric fields with changing time constants.

A circular loop of wire of radius 10 cm carries a current of 6. 0 a. what is the magnitude of the magnetic field at the center of the loop? (μ0 = 4π × 10-7 t ∙ m/a)

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