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How many grams of silver may be formed by the passage of 9,604 c through an electrolytic cell that contains a molten silver salt?

Sagot :

The grams of silver formed by the passage of 9,604 c through an electrolytic cell that contains a molten silver salt is 10.7g.

Acc. Faraday’s law of electrolysis,

W=(I×t×M) /nF

W=Faraday’s constant=96500

F=time M=molar mass

N=no. Of el.

It=9604C

Given,

Molar mass of silver=108g/mol.

n=1.

Then weight of silver deposited can be given as

W=(9604×108)/(96500×1)

= 10.7g

Thus we concluded that the silver deposited is 10.7g

learn more about faraday's law:

https://brainly.com/question/13369951

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