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A light bulb operating at 110 v draws 1. 40 a of current. what is its resistance?

Sagot :

tanisharawat014

the resistance of the circuit containing 110V and 1.42A current will be 78.57 ohm.

To find the answer, we need to know more about the Ohm's law.

How to find the resistance of the circuit?

  • Ohm's law states that, the potential difference across the ends of the conductor is proportional to the current through the conductors.

                                      [tex]V[/tex]∝ [tex]I[/tex]

                                    [tex]V=IR[/tex]

where, R is the proportionality constant called resistance of the circuit.

  • Given that, voltage is 110V, and current is 1.40A, then the resistance will be,

                        [tex]R=\frac{V}{I} =\frac{110}{1.40}=78.57Ohm[/tex]

Thus, we can conclude that, the resistance of the circuit containing 110V and 1.42A current will be 78.57 ohm.

Learn more about Resistance here:

https://brainly.com/question/22718604

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