Answered

At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Our platform offers a seamless experience for finding reliable answers from a network of experienced professionals. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

A light bulb operating at 110 v draws 1. 40 a of current. what is its resistance?

Sagot :

tanisharawat014

the resistance of the circuit containing 110V and 1.42A current will be 78.57 ohm.

To find the answer, we need to know more about the Ohm's law.

How to find the resistance of the circuit?

  • Ohm's law states that, the potential difference across the ends of the conductor is proportional to the current through the conductors.

                                      [tex]V[/tex]∝ [tex]I[/tex]

                                    [tex]V=IR[/tex]

where, R is the proportionality constant called resistance of the circuit.

  • Given that, voltage is 110V, and current is 1.40A, then the resistance will be,

                        [tex]R=\frac{V}{I} =\frac{110}{1.40}=78.57Ohm[/tex]

Thus, we can conclude that, the resistance of the circuit containing 110V and 1.42A current will be 78.57 ohm.

Learn more about Resistance here:

https://brainly.com/question/22718604

#SPJ4

Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.