Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
The vapour pressure of the solvent is 28.25 torr.
Raoult's law is a physical chemistry relationship with consequences for thermodynamics. The theory, put out by French chemist François-Marie Raoult in 1887, asserts that the partial pressure of each component of an ideal mixture of liquids is equal to the vapor pressure of the pure component (liquid or solid) multiplied by its mole fraction in the mixture. As a result, the mole fraction of the solute in the solution is equal to the relative decrease in vapor pressure of a diluted solution of a nonvolatile solute.
According to Raoult's law, p = p⁰ × x
Where,
p = partial vapour pressure of the solvent
p⁰ = vapour pressure of the solvent
x = mole fraction of solvent
The mole fraction of the pure solvent = 15 .8 /19.3
= 0.81
Substitute values in the above expression,
p = p⁰ × x
22.6 = p⁰ × 0.8
p⁰ = 28.25 torr
Therefore, the vapour pressure of the solvent is 28.25 torr.
Learn more about Raoult's law here:
https://brainly.com/question/9720507
#SPJ4
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.