Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Join our Q&A platform and connect with professionals ready to provide precise answers to your questions in various areas. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

If an ideal solution contains 3. 50 mol of a non-volatile solute and 15. 8 mol of solvent, and it has a vapor pressure of 22. 6 torr, what is the vapor pressure of the pure solvent (in torr)?

Sagot :

The vapour pressure of the solvent is 28.25 torr.

Raoult's law is a physical chemistry relationship with consequences for thermodynamics. The theory, put out by French chemist François-Marie Raoult in 1887, asserts that the partial pressure of each component of an ideal mixture of liquids is equal to the vapor pressure of the pure component (liquid or solid) multiplied by its mole fraction in the mixture. As a result, the mole fraction of the solute in the solution is equal to the relative decrease in vapor pressure of a diluted solution of a nonvolatile solute.

According to Raoult's law, p = p⁰ × x

Where,

p = partial vapour pressure of the solvent

p⁰ = vapour pressure of the solvent

x = mole fraction of solvent

The mole fraction of the pure solvent = 15 .8 /19.3

                                                               = 0.81

Substitute values in the above expression,

p = p⁰ × x

22.6 = p⁰ × 0.8

p⁰ = 28.25 torr

Therefore, the vapour pressure of the solvent is 28.25 torr.

Learn more about Raoult's law here:

https://brainly.com/question/9720507

#SPJ4