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Energy in inductors: you need an inductor that will store 20 j of energy when a 3. 0-a current flows through it. what should be its self-inductance?

Sagot :

The self inductance can be calculated as 4.444 Henry.

The inductor will store energy = 20 joule,

current = 3 ampere.

What is Self inductance?

     The current carrying conductor which allows or opposes the change of flow of current is known as self-inductance. The rate of change of current can also be given through self inductance.

Formula can be given  for the energy in the inductor as,

                      E = 1 / 2 × L × I² joule.

where as,    E - Energy

                    L - Inductance

                    I - Current flowing through the coil.

The equation can be rearranged as,

                      L =  2 E/ I²

                         =  2 × 20 / 3²

                         =  40 / 9

Hence,           L =  4.4444 Henry

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