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Sagot :
0.9544 = 95.44% of scores lie between 220 and 380 points.
Normal distribution problems can be solved using the Z-score formula.
With a set of means and standard deviations, the Z-score for measure X is given by: After finding the Z-score, look at the Z-score table to find the p-value associated with that Z-score. This p-value is the probability that the value of the measure is less than X. H. Percentile of X. Subtract 1 from the p-value to get the probability that the value of the measure is greater than X.
[tex]z = \frac{x - \mu}{\sigma} \,[/tex]
We are given mean 300, standard deviation 40.
This means that µ= 300, σ = 40
What proportion of scores lie between 220 and 380 points?
This is the p-value of Z when X = 380 subtracted by the p-value of Z when X = 220.
X = 380
[tex]z = \frac{x - \mu}{\sigma} \,[/tex]
Z= (380-300)/40
Z= 2
Z=2 has a p-value of 0.9772.
X=300
[tex]z = \frac{x - \mu}{\sigma} \,[/tex]
Z= (220-380)/40
Z=-2
Z=-2 has a p-value of 0.9772.
0,9772 - 0,0228 = 0,9544
0.9544 = 95.44% of scores lie between 220 and 380 points.
For more information about normal distribution, visit https://brainly.com/question/4079902
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