Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
The age of rock that is containing 0.628 g Uranium-238 is 2032631864.35 years.
What is half-life?
Half-life can be given as the time required by the object to reduced to half of its initial concentration. The concentration remained can be given as:
Final concentration = Initial concentration * 1/2 ^ (t/t1/2)
The initial concentration of rock has been the remaining uranium-238 and lead-206 cumulative concentration. Thus, the initial concentration is given as:
Initial concentration = Uranium-238 + Lead-206
Initial concentration = 0.068 g + 0.025 g
Initial concentration = 0.093g
The final concentration of Uranium-238 remained = 0.68 g
The half life given = 4.5 × 10⁹ years
The age (t) of the rock can be given as:
[tex]0.068=0.093\left(\frac{1}{2}\right)^{\frac{t}{4.5\times \:10^9}}\\\\\frac{t\times \:10^{-9}}{4.5}\ln \left(\frac{1}{2}\right)=\ln \left(\frac{68}{93}\right)\\\\t=2032631864.35961[/tex]
Thus, the age of rock that has remaining 0.068 g Uranium-238 is 2032631864.35 years.
Learn more about half-life, here:
https://brainly.com/question/24710827
#SPJ4
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.
