Get the answers you need at Westonci.ca, where our expert community is dedicated to providing you with accurate information. Explore our Q&A platform to find reliable answers from a wide range of experts in different fields. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
The value of trigonometry terms sin(2x) is 120/169 and cos(2x) is 119/169 and tan(2x) is 120/119.
According to the statement
We have given that the sin(x) = 5/13 , x in quadrant iii
And we have to Find the value of cos x using the following:
So, For this purpose, we know that the trigonometry terms are:
sin2(x) + cos2(x) = 1;
or cos2(x) = 1-sin2(x)
And
cos2(x) = 1-(-5/13)2 =
cos2(x) = 144/169;
We know that the
In quadrant III both the sin and cos are negative so
cos(x) = -12/13 (after taking square roots).
And
Then tan(x) = sin(x)/cos(x) = (-5/13)/(-12/13) = 5/12.
Now you can use the angle addition formulas to find sin(2x), cos(2x), and tan(2x).
Now
sin(x + x) = sinx * cosx + cosx * sinx
= (-5/13)*(-12/13) + (-12/13)(-5/13) = 120/169
And
cos(x + x) = cosX * cos(x) - sinx*sinx
= (-12/13)(-12/13) - (-5/13)(-5/13)
= 119/169
So,
You could use the tan double angle formula, but it is easiest to use
tan(2x) = sin(2x)/cos(2x) = (120/169) / (119/169)
= 120/119.
So, The value of trigonometry terms sin(2x) is 120/169 and cos(2x) is 119/169 and tan(2x) is 120/119.
Learn more about trigonometry terms here
https://brainly.com/question/13276558
#SPJ4
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.
