bribriunicorn777
Answered

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PLS HELP!!!!
The half-life of Carbon-14 is 5730 years. Suppose a fossil is found with 27% of Carbon-14 as compared to a living sample. How old is the fossil?

Sagot :

1055666

Answer: 1547.10

Step-by-step explanation: Since you are not in a physics class, in which case requires the usage of the radioactive decay formula, definite integrals, and natural logarithms) but an Algebra class which deploys the usage of percentages, this should be rather simple.

I believe they want you to find 27% of the half life of Carbon-14 since it is below 50%. To find the percent of a number (in this case 27%), you multiply the number by 0.27.

5730 * 0.27 = 1547.10

Hope this helped! And if I'm wrong, please don't hesitate to correct me.

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