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Sagot :
The flux through the paper when the paper is turned 25° with respect to field will be 22.67 [tex]Nm^{2} /C[/tex].
We have a piece of paper is held with one face perpendicular to a uniform electric field the flux through it is 25 [tex]Nm^{2} /C[/tex].
Now we have to calculate the flux through the paper if it is turned 25° with respect to the field.
What do you mean by Electric flux? What is the formula to calculate it?
Electric flux (E) through a surface is defined as the dot product of Electric field vector and Normal vector to the surface. The formula to calculate the electric flux is -
Φ = [tex]\vec{E}.\vec{A}[/tex] = E x A x cosθ
In the question it is given that when one face perpendicular to a uniform electric field the flux through it is 25 [tex]Nm^{2} /C[/tex]. In this case θ = [tex]0^{o}[/tex].
Therefore -
E x A x cos [tex]0^{o}[/tex] = 25
EA = 25 [tex]Nm^{2} /C[/tex]
When the paper is turned [tex]25^{o}[/tex] with respect to field, then the flux through it can be calculated as follows -
Φ = 25 x cos ([tex]25^{o}[/tex]) = 22.67 [tex]Nm^{2} /C[/tex].
Hence, the flux through the paper will be 22.67 [tex]Nm^{2} /C[/tex].
To solve more question on Electric flux , visit the link below -
https://brainly.com/question/14527109
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