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A weak monoprotic acid is titrated with 0.100 MNaOH. It requires 50.0 mL of the NaOH solution to reach the equivalence point. After 25.0 mL of base is added, the pH of the solution is 3.52.

Estimate the pKa of the weak acid.
Express your answer using three significant figures.


Sagot :

pKa value =4.76Ka

=1.73×10 −5 !!    PH=4−PKa=14−4.76=9.24 for a weak monoprotic acid is titrated with 0.100 M NaOH. It requires 50.0 mL of the NaOH solution to reach the equivalence point. After 25.0 mL of the base is added, the pH of the solution is 3.52.

One way to describe an acid's potency is by its pKa value. The acid dissociation constant, or pKa, is the negative log of the pKa value. A stronger acid is indicated by a lower pKa value. In other words, a lower value means that the acid dissociates in water more completely.

The logarithm of Ka's negative value is denoted as pKa. The logarithmic inverse of the H+ concentration is pH. Acidity indication. An acid's pKa value tells you if it's a strong acid or a weak acid. The pH scale shows how acidic or alkaline a system is.

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