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Sagot :
The magnitude and direction of the electrostatic torce is - 0.00712 x 10^9N towards left direction
Given:
q1 = +2 uC
q2 = -2 uC
q3 = +4 uC
To Find:
magnitude le and direction of the electrostatic torce
Solution: Electric force is a vector quantity. The electric force is proportional to the product of the magnitude of the charges. It is inversely proportional to the square of the distance between the charges. The electric force is calculated by,
F = kqQ/r^2
Force between q1 and q2
F1 = +2 x -2 x k/50 x 50 = - 0.0016k
Force between q1 and q3
F2 = +2 x +4 x k/100 x 100 = + 0.0008k
Net force on charge at origin is F1 + F2
F(net) = F1 + F2 = - 0.0016k + 0.0008k
F(net) = - 0.0008 x 8.9 x 10^9 = - 0.00712 x 10^9N
So, force on charge at origin is - 0.00712 x 10^9N and towards left direction
Learn more about Electric force here:
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