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Sagot :
The maximum velocity of electrons is v = 3.20 × 10¹⁵ m/s
The wavelength of photons λ = 85 nm
W = 4.66 ev
What is photoelectric effect and how velocity of photoelectrons is calculated?
The emission of electrons happened and absorbed through the electromagnetic radiation is said to be photoelectric effect.
Photoelectric cells, photodiodes works on the principle of photoelectric effect.
According to of photoelectric effect,
E = hν
Here, hc / λ = W + KE max
hc / λ = W + 1/2 mv² max
v² = sqrt of (( hc / λ - W) (2/m))
I cap denotes λ ,
substituting all the values,
v = sqrt of ( (6.623 × 10⁻³⁴ Js ) ( 3 × 10⁸ m/s) / (85 nm) - 4.66ev) (2/ 9.1× 10⁻³¹
v = sqrt of ((1.987800 × 10⁻²⁵ / 85 × 10 ⁹ ) - 4.66 ev ) ( 2.197 × 10³⁰)
v = sqrt of ((2.338588 × 10⁻³⁶) - 4.66 ev ) ( 2.197 × 10³⁰)3.2
v = 3.20 × 10¹⁵ m/s
Thus, the maximum velocity is calculated as v = 3.20 × 10¹⁵ m/s.
Learn more about photoelectric effect,
https://brainly.com/question/1895423
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