Answered

Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

What is the maximum velocity (in m/s) of electrons ejected from a material by 85 nm photons, if they are bound to the material by 4. 66 ev?

Sagot :

The maximum velocity of electrons is  v = 3.20 × 10¹⁵ m/s

The wavelength of photons λ = 85 nm

W = 4.66 ev

What is photoelectric effect and how velocity of photoelectrons is calculated?

     The emission of electrons happened and absorbed through the electromagnetic radiation is said to be photoelectric effect.

Photoelectric cells, photodiodes works on the principle of photoelectric effect.

According to of photoelectric effect,

                          E = hν

        Here,  hc / λ = W + KE max

                    hc / λ =  W + 1/2 mv² max

               

                   v² =  sqrt of (( hc / λ - W) (2/m))

                   I cap denotes λ ,

substituting all the values,

 v = sqrt of ( (6.623 × 10⁻³⁴ Js ) ( 3 × 10⁸ m/s) / (85 nm) - 4.66ev) (2/  9.1× 10⁻³¹

   v = sqrt of ((1.987800 ×  10⁻²⁵ / 85 × 10 ⁹ ) - 4.66 ev ) ( 2.197 × 10³⁰)          

   v = sqrt of ((2.338588 × 10⁻³⁶) - 4.66 ev ) ( 2.197 × 10³⁰)3.2

   v = 3.20 × 10¹⁵ m/s

Thus, the maximum velocity is calculated as  v = 3.20 × 10¹⁵ m/s.

Learn more about photoelectric effect,

https://brainly.com/question/1895423

#SPJ4

We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.