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550. ml of a 0. 40m solution of naoh is titrated with 0. 25 m hcl. calculate the ph of the solution after 650. ml of the hcl has been added

Sagot :

Titration is the determination of quantity by a known amount. The pH of the solution after the solution was added with 650 mL of hydrochloric acid is 13.4.

What is pH?

pH is the calculation of the hydrogen ion concentration in the solution and can be used to determine the acidity or the basicity of the solution.

Given,

M₁ = 0.40 M

V₁ = 550 mL

M₂ = 0.25 M

V₂ =?

Volume at 0.25 M is calculated as,

M₁V₁ = M₂V₂

0.40 × 550.0 =0.25 × V2

V2 = 880 ml

880 mL of HCl is required for the neutralization reaction.

The final molar concentration of NaOH is,

550 × M₁ = 0.25 × 650

M₁ = 0.295 M

pH is calculated as:

pOH = -log [OH⁻]

= -log [0.295]

= 0.529

Solving further,

pH+ pOH = 14

pH = 14 - pOH

= 14 - 0.529

= 13.4

Therefore, 13.4 is the pH of the solution.

Learn more about pH here:

https://brainly.com/question/9408394

#SPJ4

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