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Sagot :
The final answer is 29.8 mL
Molar mass HCl = 36.5 g/mol
Mol HCl in 1.85 g = 1.85 g / 36.5 g/mol = 0.05068 mol
The molarity of the HCl solution is 0.0507 mol /L
Mol HCl in 50 mL = 50 mL / 1000 mL/L * 0.0507 mol /L = 0.002535 mol
This will require 0.002535 mol NaOH
1000 mL contains 0.0850 mol
The volume that contains 0.002535 mol
Volume = 0.002535 mol / 0.0850 mol /L *1000 mL/L = 29.8 mL
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The volume of 0.0850 M NaOH is required to titrate 25.0 ml of 0.0720 M is 21.176 ml.
What are normality and molarity?
Normality is defined as the number of equivalents per litre of the solution
It is given by
Normality = number of equivalents / 1 L of solution
Molarity is defined as the number of moles of solute present in one litre of solution
Molarity = moles of solute / 1 litre of solution
Relationship between molarity and normality
Normality = Molarity × Acidity or Basicity of a salt
Here, the Acidity Of NaOH is 1 and the basicity of HBr is also 1.
Thus, Normality = Molarity
We know, N₁V₁ = N₂V₂
We can also write it as M₁V₁ = M₂V₂
V1 = [tex]\frac{M_2V_2}{M_!}[/tex]
Substitute M₁ = 0.0850 M, M₂ = 0.0720 M, V₂= 25 ml
V1 = 21.176 ml
Hence, The volume of 0. 0850 m NaOH are required to titrate 25. 0 ml of 0. 0720 m is 21.176 ml.
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