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Sagot :
The force on the electron is (F)= 9.2 nN.
How can we calculate the value of the force on the electron?
To calculate the value of the force on the electron here we use the formula,
[tex]F=k\frac{q_{1} q_{2} }{r^{2} }[/tex]
Here we are given,
[tex]q_{1}[/tex]= The charge of an atomic nucleus= 40e = [tex]40 \times 1.6 \times 10^{-19}[/tex] C.
[tex]q_{2}[/tex]= The charge of an electron = [tex]1.6 \times 10^{-19}[/tex] C.
r= The distance between the nucleus and the electron = [tex]10^{-9}[/tex] m.
k= The Coulomb's constant = [tex]8.99 \times10^9 N m ^2 /C^ 2[/tex]
We have to find the value of the of the force on the electron = F
Now , we substitute the known values in the above equation, we can get
[tex]F=k\frac{q_{1} q_{2} }{r^{2} }[/tex]
Or, [tex]F=8.99\times 10^{9} \frac{40\times 1.6\times 10^{-19} \times 1.6\times 10^{-19} }{(10^{-9})^{2} }[/tex]
Or,[tex]F=8.99\times 10^{9}\times {40\times (1.6\times 10^{-19} )^2\times (10^{9})^{2} }[/tex]
Or, [tex]F= 9.2 \times 10^{-9} N[/tex]
Or, F= 9.2nN
So, from the above calculation we can conclude that the amount of force applied on the electron is 9.2nN.
Learn more about Atomic force:
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