At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Join our platform to connect with experts ready to provide detailed answers to your questions in various areas. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
Cd2+(aq) + 2e- ---> Cd(s) , E° = -0.40 V Fe2+(aq) + 2e- ----> Fe(s) , E° = -0.44 V Since standard reduction potential.
Galvanic Cell: A chemical cell, also known as an electrochemical cell, is a device that transforms the chemical energy generated during a red-ox reaction into electrical energy. In honor of Luigi Galvanic and Alessandro Volta, who conducted the first experiments on the conversion of chemical energy into electrical energy, these are also known as galvanic or voltaic cells.
A spontaneous red-ox reaction occurs in an electrochemical cell in an indirect manner, and the reduction in free energy that occurs during the chemical reaction manifests as electrical energy. In an indirect red-ox reaction, the reduction and oxidation processes take place in two different containers known as half-cells.
learn more about galvanic cell https://brainly.com/question/20487966
#4210
The cell potential is 0.01934 V at 25°C.
What is a galvanic cell?
A galvanic cell, also known as a voltaic cell, is an electrochemical cell that converts the chemical energy generated by spontaneous redox reactions into electrical energy.
The main components of a galvanic cell are
Anode – Oxidation occurs at the anode
Cathode – Reduction occurs at the cathode
Salt bridge – consists of electrolytes that are needed to complete the circuit in a galvanic cell.
Half-cells – It is important as reduction and oxidation reactions are separated into compartments.
External circuit – it helps in Conducting the flow of electrons between electrodes
At cathode,
[tex]Cd^{2+}(aq) + 2e^-\rightarrow Cd(s)[/tex]
At anode,
[tex]Fe(s)+2e^-\rightarrow Fe^{2+}(aq)[/tex]
Overall cell reaction
[tex]Fe(s)+Cd^{2+}(aq)\rightarrow Fe^{2+}(aq) + Cd(s)[/tex]
[tex]E^o_{cell} = E^o_{cathode} - E^o_{anode}[/tex]
= -0.40 -(0.44) = 0.04 V
Nernst equation is given by
[tex]E_{cell} = E^o_{cell} - \frac{2.303RT}{nF} logQ[/tex]
At 25°C
[tex]E_{cell} = E^o_{cell} - \frac{0.0592V}{n} logQ[/tex]
Here, n = 2 and log Q = log [tex]\frac{0.250}{0.050}[/tex] = 0.699
[tex]E_{cell}[/tex] = 0.01934 V
The cell potential is 0.01934 V at 25°C
Learn more about galvanic cell:
https://brainly.com/question/13918634
#SPJ4
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.
