Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Explore our Q&A platform to find reliable answers from a wide range of experts in different fields. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
The pH of a 0.50 M solution of base B is found to be 10.19. The Kb of the base is 4.8 × 10⁻⁸.
Let's consider the following basic reaction.
B(aq) + H2O(l) ⇄ BH(aq) + OH⁻(aq)
First, we will calculate the pOH of the solution using the following expression. (14-10.19)=3.81
antilog -3.81=1.55×10^-4/0.50=4.8×10^-8
The pH of a 0.50 M solution of base B is found to be 10.19. The Kb of the base is 4.8 × 10⁻⁸.
Learn more about Kb for this base here brainly.com/question/6465134
#4262
The [tex]K_b[/tex] of the base b is 4.805 × 10⁻⁸.
What is dissociation constant?
The dissociation constant is a type of equilibrium constant that measures the degree of dissociation of a salt.
[tex]K_a[/tex] is the dissociation constant for the acid which describes the strength of an acid.
[tex]K_b[/tex] is the dissociation constant of the base which describes the strength of a base.
pOH = 14 - pH = 14 - 10.19 = 3.81
pOH = -log[OH⁻]
3.81 = -log[OH⁻]
Antilog (-3.81) = [OH⁻]
[OH⁻] = 1.55 × 10⁻⁴
Here,
[tex]K_b= \frac{[BH^+][OH^-]}{[B]}[/tex]
= [tex]\frac{(1.55\times10^{-4})(1.55\times10^{-4})}{0.50}[/tex]
= 4.805 × 10⁻⁸
The Kb of the base b is 4.805 × 10⁻⁸
Learn more about dissociation constant:
https://brainly.com/question/9560811
#SPJ4
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.
