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The boiling point of a solution consisting of cyclohexane (c6h12) dissolved in benzene if the freezing point of this solution is 0. 0°c is 80.9°C.
When a solute and a solvent are combined to form a liquid homogeneous mixture or solution, the properties that result are different from those of the pure substances. As a result, we can find a freezing point depression, boiling point elevation, and a few other cooperative properties, but these two are the focus of this article.
Taking into account that the freezing point depression constant solely depends on the solvent (cyclohexane), we can begin by utilizing the freezing point depression to determine the molality of the solution:
[tex]T_{fsolution} - T_{fsolvent} = -m * {K_{fsolvent}[/tex]
0. 0°c - 5.5°c = -m * 20.0 °c
[tex]m = \frac{-5.5}{- 20.0 }[/tex]
m = 0.275 m
The boiling point elevation formula is then used to get the solution's boiling point, which is once more dependent on the solvent's boiling point elevation constant:
[tex]T_{b, solution} - T_{b, solute} = m * Kb_{solvent} \\\\T_{b, solution} - 80.1 = 0.275m + 2.79\\\\T_{b, solution} = 80.9[/tex]
Therefore, The boiling point of a solution is 80.9°C.
To know more about boiling point refer to: https://brainly.com/question/14895798
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