Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Get quick and reliable answers to your questions from a dedicated community of professionals on our platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
The ideal diode's current is 0.064 mA at a forward biased voltage drop of 65 V.
An ideal diode is a particular kind of electronic component that has two terminals, and only permits current to flow in one direction, with less zero resistance in one direction and infinite resistance in another.
The most often used type of diode is a semiconductor diode.
It is a crystalline semiconductor part with a PN junction that is connected to two electrical terminals.
We have provided values here.
[tex]V_{2}[/tex]=65 volts
[tex]v_{1} =6v[/tex]
[tex]r_{1} =921w[/tex]
[tex]I=V_{2 - V_{1} /I[/tex]= 65-6/921=0.064
The ideal diode's current is 0.064 mA at a forward biased voltage drop of 65 V.
Here is further information about the ideal diode:
brainly.com/question/14988926
#SPJ1
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.