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A 1. 7 m solution of the acid ha has a ph of 1. 0. what is the ka of the acid? the equation described by the ka value is ha(aq) h2o(l)⇌a−(aq) h3o (aq)

Sagot :

A 1. 7 m solution of the acid ha has a ph of 1. 0, then the ka of the acid is 6.25×10^(-3).

What is acid dissociation constant?

The acid dissociation constant is defined as the value which is used to measure the strength of the specific acid in the solution.

Equation for general dissociation of strong or weak acid is

HA ----- (H+) + ( A-)

Ka can be expressed as

Ka = [H+] [A-]/[HA]

where [H+] is the concentration of H+ ions

Now, we will find the value of concentration of H+ ions

pH = -log [H+]

1 = -log[H+]

[H+] = antilog(-1)

[H+] = 0.1

By using ICE table, we find that the concentration of [HA] is

1.7-0.1

= 1.6

By substituting all the values we get,

Ka = 0.1 × 0.1/1.6

= 6.25×10^(-3)

Thus, we find that the Ka value of the given solution is 6.25×10^(-3).

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