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What is the relationship between acceleration and time a(t) for the model rocket (v(t)=αt3 βt γ, where α=−3. 0m/s4, β=36m/s2, and γ=1. 0m/s)?

Sagot :

The relationship between acceleration and time a(t) for the model rocket v(t)=αt³ + βt + γ, where α=−3. 0m/s4, β=36m/s2, and γ=1. 0m/s is a(t) = -9t² + 36 m/s²

The differentiation of velocity with respect to time gives acceleration.

Velocity of a rocket model is the speed acquired of the body in a particular direction.

Acceleration of the body is the change in velocity with respect to time.

v(t)=αt³ + βt + γ

On differentiating,

a = 3αt² + β

Given, α=−3. 0m/s⁴

           β=36m/s²

            γ=1. 0m/s

On subsituting,

                 a = 3(-3)t² + 36 m/s²

Hence, relationship between acceleration and time a(t) = -9t² + 36 m/s²

Learn more about acceleration here, https://brainly.com/question/12550364

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