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Sagot :
The discrete probability distribution that finds the probability that x exceeds 5 is 0.38
Opportunity provides records approximately the likelihood that something will manifest. Meteorologists, for instance, use weather patterns to are expecting the chance of rain. In epidemiology, the probability idea is used to recognize the connection between exposures and the risk of fitness consequences.
Finding the possibility of a simple event happening is fairly straightforward: upload the changes collectively. For example, if you have a 10% chance of triumphing $10 and a 25% threat of triumphing $20 then your normal odds of prevailing something is 10% + 25% = 35%.
If there is no ambiguity within the occurrence of an occasion, then the chance of such an occasion is equal to 1. In other phrases, the chance of a sure occasion is 1. If an occasion has no probability of taking place, then its chance is zero.
We want to find the probability for x exceeding 5 means for x>5
Consider,
P(X>5)=P(x=6)+P(X=8)
=0.18+0.2
=0.38
Hence, the probability is 0.38
Learn more about probability here https://brainly.com/question/24756209
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