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Sagot :
44.58% is the maximum theoretical efficiency possible for an engine operating between 100°c and 400°c
The ratio of useful work completed to heat produced is used to determine an engine's efficiency. is the task finished.
Please be aware that the phrase "work done" refers to the force applied to the clutch or driveshaft. This implies that the work produced by thermodynamic expansion is reduced by the friction and other losses.
Given
T1 = 100 +273 = 373K
T2 = 400 + 273 = 673 K
Formula for efficiency = (T2 -T1/T2) × 100
Put the values of T1 and T2
We get
Efficiency = (673 - 373 /673) × 100
Efficiency = 44.58%
Learn more about engine efficiency here https://brainly.com/question/23719522
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