Discover a wealth of knowledge at Westonci.ca, where experts provide answers to your most pressing questions. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
27.94 g/mole is the molar mass of the unknown gas.
Use Graham's Law, which indicates that the square root of a gas's molar mass determines its rate of effusion.
The following equation compares two distinct gases, (a) and (b), and expresses this:
sqrt(M(b)/M) = R(a)/R(b) (a)
R is the effusion rate.
square root = sqrt
the molar mass, M
In response to your query, if gas (a) is the unknown gas and Xe(M = 131 g/mol) is the second gas, we have:
sqrt(M(Xe)/M(a) = 2.165, where R(a)/R(Xe)
Square both sides, and you get:
(2.165)² = 131 g/mol/ M (a)
M(a)(2.165)² = 131
M(a) is equal to 131/(2.165)² = 27.94 g/mol.
Having a molar mass of 27.94 g/mol, the unknown gas.
Learn more about Graham's law of effusion here https://brainly.com/question/22359712
#SPJ4
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.
