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Sagot :
The concentration of [ Hy³] = 4.861 *28⁻²³
The concentration of a solution is a measure of the amount of solute that has been dissolved in a given amount of solvent or answer. A focused answer is one which has a exceedingly massive quantity of dissolved solute. A dilute answer is one that has a tremendously small amount of dissolved solute.
Given,
Molarity of VoSo4 ,M = 0.02M
Vol of VoSo4 , V = 10 ml
Molarity of EDTA = 0.02 M
vol of EDTA = 9.10 ml = 0.0091 L
& 10 ml of buffer with pH =4
NOW,
no. of moles of EDTA = molarity * Volume (L)
= 0.02 M * 0.0091 L
= 182 * 10^-6 moles
= 1.82 * 10^-4 moles
Now,
∝ Y^3- = [tex]\frac{[Y^3-]}{moles of edta}[/tex]
[ Y^3-] = ∝ Y^3- * moles of EDTA
Given,
at pH = 4, ∝ Y^3- = 3*10^-9
∴ ∝ Y^3- = 3*10^-9
[ Y^3-] = 3*10^-9 * 1.82 * 10^-4
= 5.46 * 10^-13
Now, K f = [H2Y^2-]/[vo^2+][y3-]
[vo^2+] = 18.7
[H2Y2-] = K f * [ v o+][Y^2-]
[H2Y2] = 3.762 * 10^-13
[ HY^3-] = 4.8 * 10^-23
So, the concentration of the [ HY^3-] is 4.8 * 10^-23
Learn more about Concentration here:-https://brainly.com/question/17206790
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