Calculate [hy3−] in a solution prepared by mixing 10. 00 ml of 0. 0305 m voso4, 9. 20 ml of 0. 0305 m edta, and 10. 00 ml of buffer with a ph of 4. 0

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02-08-2022
Chemistry

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Calculate [hy3−] in a solution prepared by mixing 10. 00 ml of 0. 0305 m voso4, 9. 20 ml of 0. 0305 m edta, and 10. 00 ml of buffer with a ph of 4. 0

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kjuli1766 kjuli1766 · Answer 1 · 2022-08-09T18:03:36-04:00

The concentration of [ Hy³] = 4.861 *28⁻²³

The concentration of a solution is a measure of the amount of solute that has been dissolved in a given amount of solvent or answer. A focused answer is one which has a exceedingly massive quantity of dissolved solute. A dilute answer is one that has a tremendously small amount of dissolved solute.

Given,

Molarity of VoSo4 ,M = 0.02M

Vol of VoSo4 , V = 10 ml

Molarity of EDTA = 0.02 M

vol of EDTA = 9.10 ml = 0.0091 L

& 10 ml of buffer with pH =4

NOW,

no. of moles of EDTA = molarity * Volume (L)

= 0.02 M * 0.0091 L

= 182 * 10^-6 moles

= 1.82 * 10^-4 moles

Now,

∝ Y^3- = [tex]\frac{[Y^3-]}{moles of edta}[/tex]

[ Y^3-] = ∝ Y^3- * moles of EDTA

Given,

at pH = 4, ∝ Y^3- = 3*10^-9

∴ ∝ Y^3- = 3*10^-9

[ Y^3-] = 3*10^-9 * 1.82 * 10^-4

= 5.46 * 10^-13

Now, K f = [H2Y^2-]/[vo^2+][y3-]

[vo^2+] = 18.7

[H2Y2-] = K f * [ v o+][Y^2-]

[H2Y2] = 3.762 * 10^-13

[ HY^3-] = 4.8 * 10^-23

So, the concentration of the [ HY^3-] is 4.8 * 10^-23

Learn more about Concentration here:-https://brainly.com/question/17206790

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