Answered

Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Our Q&A platform provides quick and trustworthy answers to your questions from experienced professionals in different areas of expertise. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

The equilibrium constant for the following reaction:
Ca(HCO3)2(s) <--> CaO(s) + 2 CO2(g) + H2O(g)
would be:
Group of answer choices

A. K = [Ca(HCO3)2] / [CaO][CO2]2[H2O]

B. K = [CaO][CO2]2[H2O] / [Ca(HCO3)2]

C. K = [CO2]2[H2O]

D. K = [CO2]2[H2O] / [Ca(HCO3)2]

Sagot :

CrystalQueen

Answer:

C.) [tex]K = {[CO_{2} ]^{2} [H_2O] }[/tex]

Explanation:

The general equilibrium expression looks like this:

[tex]K = \frac{[B]^b[C]^{c} [D]^{d} }{[A]^{a}} }[/tex]

In this expression,

-----> K = equilibrium constant

-----> uppercase letters = formulas

-----> lowercase letters = balanced equation coefficients

Solids are not included in the expression, so Ca(HCO₃)₂(s) and CaO(s) should be left out. The products should be in the numerator and the reactants are in the denominator. This makes the expression:

[tex]K = \frac{[B]^b[C]^{c} [D]^{d} }{[A]^{a}} }[/tex]                                  <----- Equilibrium expression

[tex]K = {[CO_{2} ]^{c} [H_2O]^{d} }[/tex]                             <----- Insert gaseous formulas

[tex]K = {[CO_{2} ]^{2} [H_2O] }[/tex]                               <----- Insert coefficients

Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.