Answered

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The equilibrium constant for the following reaction:
Ca(HCO3)2(s) <--> CaO(s) + 2 CO2(g) + H2O(g)
would be:
Group of answer choices

A. K = [Ca(HCO3)2] / [CaO][CO2]2[H2O]

B. K = [CaO][CO2]2[H2O] / [Ca(HCO3)2]

C. K = [CO2]2[H2O]

D. K = [CO2]2[H2O] / [Ca(HCO3)2]

Sagot :

CrystalQueen

Answer:

C.) [tex]K = {[CO_{2} ]^{2} [H_2O] }[/tex]

Explanation:

The general equilibrium expression looks like this:

[tex]K = \frac{[B]^b[C]^{c} [D]^{d} }{[A]^{a}} }[/tex]

In this expression,

-----> K = equilibrium constant

-----> uppercase letters = formulas

-----> lowercase letters = balanced equation coefficients

Solids are not included in the expression, so Ca(HCO₃)₂(s) and CaO(s) should be left out. The products should be in the numerator and the reactants are in the denominator. This makes the expression:

[tex]K = \frac{[B]^b[C]^{c} [D]^{d} }{[A]^{a}} }[/tex]                                  <----- Equilibrium expression

[tex]K = {[CO_{2} ]^{c} [H_2O]^{d} }[/tex]                             <----- Insert gaseous formulas

[tex]K = {[CO_{2} ]^{2} [H_2O] }[/tex]                               <----- Insert coefficients

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