Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Discover a wealth of knowledge from experts across different disciplines on our comprehensive Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
The wavelength of the emitted photon is([tex]\lambda[/tex])= 690nm
How can we calculate the wavelength of the emitted photon?
To calculate the wavelength of the photon we are using the formula,
[tex]\triangle E= \frac{h\times c}{\lambda}[/tex]
Or,[tex]\lambda= \frac{h\times c}{\triangle E}[/tex]
We are given here,
[tex]\triangle E[/tex]= The energy difference between the two levels = 1. 8 ev= [tex]1.8\times 1.6 \times 10^{-19}[/tex] C.
h= Planck constant = [tex]6.626\times 10^{-34}[/tex] Js.
c= speed of light = [tex]3\times10^8[/tex] m/s.
We have to find the wavelength of the emitted photon =[tex]\lambda[/tex] m.
Therefore, we substitute the known parameters in the above equation, we can find that,
[tex]\lambda= \frac{h\times c}{\triangle E}[/tex]
Or,[tex]\lambda= \frac{6.626\times 10^{-34}\times 3\times 10^8}{1.8\times 1.6 \times 10^{-19}}[/tex]
Or,[tex]\lambda= 690\times 10^{-9}[/tex] m
Or,[tex]\lambda[/tex]=690 nm.
From the above calculation we can conclude that the wavelength of the emitted photon is 690nm.
Learn more about ruby laser:
https://brainly.com/question/17245697
#SPJ4
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.
