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Sagot :
The local minimum over the interval [-3,-1] is 0, the local maximum over the interval [-1,0] is 4.39, local minimum over the interval[0,3]is -32.
Given a graph of a function.
We are required to find:
A)Local minimum over the interval [-3,-1],
B) Local maximum over the interval [-1,0],
C) Local minimum over the interval [0,3].
We know that local maximum is a point after which the value of function starts decreasing and the local minimum is a point after which the value of function starts increasing.
When we see the graph from x=-3 to x=-1 we can find that the highest point is where the value of f(x) is minimum and after which the graph is increasing is at x=-2 and y=0, so the value of local minimum will be 0.
When we see the graph from x=-1 to x=0 we can find that the highest point is where the value of f(x) is maximum and after which the graph is decreasing is at y=4.39, so the value of local maximum will be 4.39.
When we see the graph from x=0 to x=3 we can find that the highest point is where the value of f(x) is minimum and after which the graph is increasing is at y=-32, so the value of local minimum will be -32.
Hence the local minimum over the interval [-3,-1] is 0, the local maximum over the interval [-1,0] is 4.39, local minimum over the interval[0,3]is -32.
Learn more about function at https://brainly.com/question/10439235
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