Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
If the probability of obtaining success is 0.3 and the value of n is 9 then the probability at the value of x be 3 is 0.3811.
Given that the value of n is 9 and the value of p is 0.3.
We are required to find the probability when the value of x is equal to 3.
Probability is the calculation of chance of happening an event among all the events possible.It lies between 0 and 1.
Probability=Number of items/total items.
Binomial probability is basically the probability of exactly x successes on n repeated trials in an experiment which has two possible outcomes.
[tex](a+b)^{n}[/tex]=[tex]nC_{0}a^{0} b^{n-0} +nC_{1}a^{1} b^{n-1} +................nC_{n}a^{n} b^{0}[/tex]
We have to find the value when n=9, p is 0.3 and r=3.
=[tex]9C_{3} (0.3)^{3} (1-0.3)^{6}[/tex]
=9!/3!6!*0.027*0.16807
=84*0.00453789
=0.381182
Hence if the probability of obtaining success is 0.3 and the value of n is 9 then the probability at the value of x be 3 is 0.3811.
Learn more about probability at https://brainly.com/question/24756209
#SPJ4
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.
