Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Our Q&A platform provides quick and trustworthy answers to your questions from experienced professionals in different areas of expertise. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
32.88grams of (Ag) silver would plate onto the pure electrode if a current of 6. 8A flowed through the cell for 72 minutes.
Silver can be electroplated at the cathode of an electrolysis cell by the half-reaction:
Ag+(aq)+e→Ag(s).
By Using the equation
Q= I×t, where Q = charge
I = current = 6.8 A
t= time in seconds= 72×60=4320s
So,
Q=6.8×4320
Q = 29,376C
We see that 1 mole of electrons produces 1 mole of Ag from the half reaction.
1mole of electrons= 96,500C
xmoles of electrons= 29,376C
Cross multiplying;
29,376= 96,500 × x
Now , dividing both sides of the by 96,500
29,376/96,500=x
0.3044 moles of electrons will produce
0.3044×108 = 32.88grams of Ag
Therefore, 32.88grams of (Ag) silver would plate onto the pure electrode if a current of 6. 8A flowed through the cell for 72 minutes.
Learn more about Ag here;
https://brainly.com/question/3023145
#SPJ4
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We appreciate your time. Please come back anytime for the latest information and answers to your questions. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.
