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Calculate how many moles of nh3 form when each quantity of reactant completely reacts?

Sagot :

3.6 moles [tex]NH_{3}[/tex] required when each quantity of reactant completely reacts.

The ratio of the mole quantities of any two compounds present in a balanced chemical reaction is known as the mole ratio. A reaction's product yield can be predicted using mole ratios, as can the amount of reactant required to produce a specific amount of result.

The balanced chemical equation is :

[tex]3N_{2} H_{4}[/tex](l) → [tex]4NH_{3}[/tex](g) + [tex]N_{2}[/tex](g)

Given is = 2.6 mol [tex]N_{2} H_{4}[/tex]

As we see, 3 moles of [tex]N_{2} H_{4}[/tex] reacts with  4 moles of [tex]NH_{3}[/tex].

Therefore,

n( [tex]NH_{3}[/tex]) = n(  [tex]N_{2} H_{4}[/tex] ) × [tex]\frac{4}{3}[/tex]

n( [tex]NH_{3}[/tex]) = [tex]2.6mol^{*} \frac{4mol}{3mol}[/tex]

n( [tex]NH_{3}[/tex]) = 3.6 moles.

Therefores, 3.6 moles [tex]NH_{3}[/tex] required when each quantity of reactant completely reacts.

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