Looking for answers? Westonci.ca is your go-to Q&A platform, offering quick, trustworthy responses from a community of experts. Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
The time elapsed is 3229.2 days.
First-order reactions include those in radioactive decay. The reduction in radioactive nuclei per unit of time is the rate of decay, or activity, of a sample of a radioactive substance.
The Radioactive Formula is given by
[tex]N =[/tex] N₀ [tex](\frac{1}{2} )^\frac{t}{T}[/tex]
Where N₀ = The initial quantity of the substance.
N = The quantity remained.
T = the half-life of the decaying quantity.
t = time elapsed
The initial quantity of the substance = 4.0 g
The quantity remained = 1.0 g
The half-life of the decaying quantity = 1620 years
Using formula;
[tex]1.0 = 4.0 (\frac{1}{2} )^\frac{t}{1620} \\[/tex]
[tex]log \frac{1.0}{4.0} = \frac{1}{1620} log \frac{1}{2}\\[/tex]
[tex]log 0.25 = \frac{t}{1620} log 0.5\\[/tex]
[tex]-0.60 = \frac{t}{1620} (-0.301)\\[/tex]
[tex]t = \frac{972}{0.301} \\[/tex]
[tex]t= 3229.2 sec[/tex]
Therefore, the time elapsed is 3229.2 days
Learn more about radioactive here:
https://brainly.com/question/23566209
#SPJ4
We appreciate your time. Please come back anytime for the latest information and answers to your questions. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.