Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
The time elapsed is 3229.2 days.
First-order reactions include those in radioactive decay. The reduction in radioactive nuclei per unit of time is the rate of decay, or activity, of a sample of a radioactive substance.
The Radioactive Formula is given by
[tex]N =[/tex] N₀ [tex](\frac{1}{2} )^\frac{t}{T}[/tex]
Where N₀ = The initial quantity of the substance.
N = The quantity remained.
T = the half-life of the decaying quantity.
t = time elapsed
The initial quantity of the substance = 4.0 g
The quantity remained = 1.0 g
The half-life of the decaying quantity = 1620 years
Using formula;
[tex]1.0 = 4.0 (\frac{1}{2} )^\frac{t}{1620} \\[/tex]
[tex]log \frac{1.0}{4.0} = \frac{1}{1620} log \frac{1}{2}\\[/tex]
[tex]log 0.25 = \frac{t}{1620} log 0.5\\[/tex]
[tex]-0.60 = \frac{t}{1620} (-0.301)\\[/tex]
[tex]t = \frac{972}{0.301} \\[/tex]
[tex]t= 3229.2 sec[/tex]
Therefore, the time elapsed is 3229.2 days
Learn more about radioactive here:
https://brainly.com/question/23566209
#SPJ4
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.