Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

Use the laplace transform to solve the given initial-value problem. y'' − 8y' 16y = t, y(0) = 0, y'(0) = 1

Sagot :

If the initial value problem is [tex]y^{11} -8y^{1} -15y=0[/tex] and [tex]y^{1}(0) =1[/tex],y(0)=0 then y(t)=[tex](e^{3t} -e^{5t} )/2[/tex].

Given the initial value problem be   [tex]y^{11} -8y^{1} -15y=0[/tex]and  [tex]y^{1}(0) =1[/tex],y(0)=0.

We are required to find the solution of the given initial value problem.

Laplace transform is an integral transformation that converts a function of a real variable to a function of a complex variable.

Take laplace on the DE, we get

[tex]s^{2}-sY(0)-y^{i}(0)-8[sY(s)-y(0)-15Y(s)]=0[/tex]

[tex]s^{2}Y(s)-s(0)-1-8{sY(s)-0)}+15Y(s)=0[/tex]

(Putting the values given in question)

Y(s)=([tex]s^{2} -8s+15)-1=0[/tex]

Y(s)=1/([tex]s^{2} -8s+15[/tex])

Simplifying the above:

=1/([tex]s^{2} -5s-3s+15)[/tex]

=1/[s(s-5)-3(s-5)]

=1/2 [1/(s-3)-1/(s-5)]

Taking inverse of the above we get,

y(t)=[tex](e^{3t} -e^{5t} )/2[/tex]

Hence if the initial value problem is [tex]y^{11} -8y^{1} -15y=0[/tex] and [tex]y^{1}(0) =1[/tex],y(0)=0 then y(t)=[tex](e^{3t} -e^{5t} )/2[/tex].

Learn more about laplace transform at https://brainly.com/question/17062586

#SPJ1