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Sagot :
The spring stiffness constant is 796.25 N/m.
A spring's "spring constant" is a property that quantifies the relationship between the force acting on the spring and the displacement it produces.
The slope of the plot of the straight line W vs x represents the spring constant, K. Weight (W) is defined as mass times the gravitational acceleration (g), where g is equal to approximately 980 cm/sec².
Mass of the fish = 2.6 kg
Length of the fisherman's scale, x = 3.2 cm
= 3.2/100 m
= 0.032 m
We have to find the value of k;
We know that,
F = - kx
Where k is the spring constant,
F is the force applied over x
x is the displacement by the spring expressed in N/m.
mg = - kx
g = 9.8 m/s²
[tex]K = \frac{mg}{x}[/tex]
[tex]= \frac{2.6*9.8}{0.032}[/tex]
[tex]= 796.25 N/m[/tex]
Therefore, the spring's constant is 796.25 N/m.
Learn more about spring constant here:
https://brainly.com/question/23885190
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