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A fisherman's scale stretches 3. 2 cm when a 2. 6 kg fish hangs from it. part a what is the spring stiffness constant?

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tushargupta0691

The spring stiffness constant is  796.25 N/m.

A spring's "spring constant" is a property that quantifies the relationship between the force acting on the spring and the displacement it produces.

The slope of the plot of the straight line W vs x represents the spring constant, K. Weight (W) is defined as mass times the gravitational acceleration (g), where g is equal to approximately 980 cm/sec².

Mass of the fish = 2.6 kg

Length of the fisherman's scale, x = 3.2 cm

                                                          = 3.2/100 m

                                                          = 0.032 m

We have to find the value of k;

We know that,

                       F = - kx

Where k is the spring constant,

           F is the force applied over x

           x is the displacement by the spring expressed in N/m.

                       mg = - kx

                       g = 9.8 m/s²

                       [tex]K = \frac{mg}{x}[/tex]

                           [tex]= \frac{2.6*9.8}{0.032}[/tex]

                           [tex]= 796.25 N/m[/tex]

Therefore, the spring's constant is 796.25 N/m.

Learn more about spring constant here:

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