A 26-meter-tall statue of buddha in tibet is covered with
279 kg of gold. if the gold was applied to a thickness of
0.0015 mm, what surface area is covered in square
meters)? (gold density = 19.3 g/cm)

Question

shyiann1981 shyiann1981

02-08-2022
Chemistry

Answered

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A 26-meter-tall statue of buddha in tibet is covered with
279 kg of gold. if the gold was applied to a thickness of
0.0015 mm, what surface area is covered in square
meters)? (gold density = 19.3 g/cm)

Sagot :

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tutorconsortium201 tutorconsortium201 · Answer 1 · 2022-08-08T11:24:38-04:00

0.014559 g/cm³ is the surface area that covered in square.

Definition of surface area -

To recall, the surface area of an object is the total area of the outside surfaces of the three-dimensional object i.e, the total sum of the area of the faces of the object. It is measured in terms of square units.
The amount of area covered by the surface of something. The lake has roughly the same surface area as 10 football fields.

The surface area is calculated as -

Conversion of units -

[tex]26 m * \frac{100 cm}{1 m} = 2600 cm[/tex]

[tex]279 kg * \frac{1g}{1000 kg} = 0.279 g[/tex]

[tex]0.0015 mm * \frac{0.1 cm}{1mm} = 0.00015 cm[/tex]

Now we use formula for volume -

[tex]Volume = \frac{mass}{density}[/tex]

[tex]= \frac{0.279 g}{19.3 g/ cm^{3} }[/tex]

= 0.014559 g/cm³

Learn more about surface area

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A 26-meter-tall statue of buddha in tibet is covered with 279 kg of gold. if the gold was applied to a thickness of 0.0015 mm, what surface area is covered in square meters)? (gold density = 19.3 g/cm)

Sagot :

Other Questions

A 26-meter-tall statue of buddha in tibet is covered with
279 kg of gold. if the gold was applied to a thickness of
0.0015 mm, what surface area is covered in square
meters)? (gold density = 19.3 g/cm)