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What average emf (in volts) is induced, given the plane of the coil is originally perpendicular to the earth’s field and is rotated to be parallel to the field in 11 ms?

Sagot :

The average emf induced is "ωBA volts".if we know the value of ω, B & A we can easily calculate the value. Faraday's law of induction determines the typical emf produced by spinning a coil's turn in the earth's magnetic field.

Discussion:

According to this equation, the magnetic flux through a closed loop changes at a time rate equal to the negative of the induced emf in the loop.

  • When a coil is exposed to a magnetic field, it encounters a flux that is equal to the magnetic field's intensity times the area that the loop encloses times the Sine of the angle that exists between the standard to the region and the magnetic field.

Calculation:

This flux value is constant and no electromagnetic field (EMF) is produced when the loop is positioned in the earth's magnetic field without moving. When the magnetic field starts rotating, the area and magnetic field strength stay constant, but the angle between the plane of the area's normal and the field lines continues to alter or fluctuate. Due to the magnetic flux's relationship to angle and the time dt at which an average emf is produced in the coil, this results in a change in the net magnetic field across the loop.

The flux φ = BAcosθ

E = - dφ/dt = - d(BAcosθ)/dt

As "B" & "A", both are constant

so, E= - BAd(cosθ)/dt

where, θ = the function of time

θ = ωt

where, ω = angular frequency (rad/sec)

E = -BAd(Cosωt)/dt

E = - (-ω)BA Sinωt = ωBA Sinωt

E = ωBASinωt

E = -d(BACosθ)/dt

The plane is now parallel to the field, and the normal is now perpendicular to the field.

θ=90°

Therefore, E= ωBASin90° = ωBA(1) = ωBA

Learn more about the magnetic fields here:

https://brainly.com/question/14848188

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