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Sagot :
The wavelength of photon in 2 significant is 4.8 × 10∧3 angstrom
Given: Mass of photon= Mass of electron= 9.11×10^-31 kg
Velocity= 1500m/s
Planck constant(h)= 6.6261*10^-34 Js
λ= h/mv= 6.6261*10^-34 Js/(9.11×10^-31× 1500)kgm/s
= 4.8 × 10^3 angstrom
About De-brogile wavelength:
De Broglie stated that every particle could be described as having a particular wavelength and formulated the famous de Broglie equation.
De Broglie asserts that a beam of particles with a certain mass can act like a matter wave. The particle's mass and velocity are related to its wavelength:
λ= h/mv, where,
- m is the particle's mass.
- v represents the particle's speed.
- The Planck constant, or h, has a value of 6.6261*10^-34 Js.
Learn more about wavelength here:
https://brainly.com/question/13533093
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