Answered

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A mass m is attached to an ideal massless spring with spring constant k. In experiment 1 the mass oscillates with amplitude a, and period t. A student grabs the mass and brings it to rest before starting experiment 2. In experiment 2, the mass is set to oscillate with a larger amplitude of 3a. What is the period of the oscillation in experiment 2?.

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Time period remains the same in both the experiment as change in amplitude does not affect time period.

What are the factors on which time period depends in SHM?

Time period is given by:

[tex]T = 2\pi \sqrt{\frac{m}{k} }[/tex]

where,

T = time period

m = mass

k = spring constant

From the given formula, we find that the time period is only dependent on mass of the object and spring constant in a simple harmonic motion (SHM). If there is any change in mass of the object or the spring constant, the time period will change accordingly.

Learn more about SHM here:

https://brainly.com/question/20885248

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