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Sagot :
the temperature of the source is 159.884°C
How to determine the temperature of the source ?
given data:-
λmax=6.69
by using weins law:- Wien’s law, also called Wien’s displacement law, relationship between the temperature of a blackbody (an ideal substance that emits and absorbs all frequencies of light) and the wavelength at which it emits the most light .The wavelength at which maximum radiation is emitted is expressed by the Greek letter “ λ ”.T is the object's temperature in Kelvin, and the constant is 2,897 μm.The higher the object's temperature, the faster the molecules will vibrate and the shorter the wavelength will be.
λmax = constant / temperature(in kelvin) temperature(in kelvin) = constant/λmax temperature(in kelvin) =2897/6.69
temperature(in kelvin)=433.03
temperature(in celsius) = temperature(in kelvin)-273.15
temperature(in celsius)= 159.88
Thus from the above conclusion we can say that at peak wavelength at 6. 69 µm the temperature is 159.884°C.
Learn more about the weins law here: https://brainly.in/question/15651476
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