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Find the general solution of the given higher-order differential equation. y''' − 9y'' 15y' 25y = 0

Sagot :

The general solution of the given higher-order differential equation. y''' − 9y'' 15y' 25y = 0 is Y= c1e^-x +c2e^5x + c3xe^5x

m^3 -9m^2+15m+25=0

Possible rational roots = 1,-1,5,-5,25

Now on putting these possible rational roots which have been found by the discriminant and hit and trial method,

we will check these roots.

m=-1 comes out to be a root of the equation.

m^2-10m+25=0

(m-5)(m+5)=0

(m-5)^2=0

m=5

So the general equation comes out to be

Y= c1e^-x +c2e^5x + c3xe^5x

For more information about differential equations, visit

https://brainly.com/question/1164377

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